Rewrite y = x2 +6x+ 10 in graphing (vertex) form by completing the square. State the VERTEX.

The vertex is (-3,1)

Step-by-step explanation:

Here, we want to write the given function in the vertex form

Mathematically, we have this as;

y = a(x-h)^2 + k

where the vertex is (-h,k)

Thus, we have

Let us divide the coefficient of x by 2, square and add to both sides ; prior to this, we will equate y to 0

Thus, we have it that;

0 = x^2 + 6x + 10

x^2 + 6x + 10 + 9 = 9

x^2 + 6x + 9 = 9-10

x^2 + 6x + 9 = -1

(x + 3)^2 = -1

(x + 3)^2 + 1 = 0

So the vertex here as represented by (-h,k) is;

(-3,1)

2/3

step-by-step explanation:

you can not solvr this without numbers