The area of a bookmark is 140 square centimeters. The perimeter is 54 centimeters. What are the dimensions of the bookmark?

See explanation

Step-by-step explanation:

Recall that all the sides of the square are equal

Hence;

Area of a rectangle= l * b equation 1

Perimeter of a rectangle = 2(l + b)equation 2

Area of the rectangle = 140 square centimeters

140 = lb

l = 140/b

Perimeter of the rectangle =  54 centimeters

substituting l = 140/b into equation 2

54 = 2(140/b + b)

Multiplying through by b

54b = 280 + 2b^2

Hence;

2b^2 - 54b + 280 = 0

Solving the quadratic equation

b=20 or b=7

substituting b=20 or b=7 into l = 140/b

l = 140/20 or l = 140/7

l = 7 or 20

THEREFORE;

b=20 cm or b=7 cm

l = 7cm or 20cm

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

35x 3= 105

step-by-step explanation:

35+35= 70   70 + 35= 105