Please answer :( im very lonely and im bad at maths so do it for me :(((

Step-by-step explanation:

First you need to calculate the entire length (in meters) of the metal used in the gate, then multiple the length by 2.5 kg per meter

Break it into parts.......

four pieces on along the outside is just the perimeter of a rectangle

         P = 2( L + H)        both sides and the top and bottom

the two crossing metal pieces are just the hypotenuse of a right triangle and since we have two pieces of metal

        a² + b² = c²     or   L² + H² = Hyp²          solving for the htpotenuse

                         Hyp =              

so the total length of the gate metal is

P = 2( L + H)    plus        2 Hyp =  

   = 2( 12 + 5)      +     2 [ √(12² + 5²) ]

   =       34          +   2 [ √( 144 + 25) ]

   =       34  +  2 ( √169)

   =       34 +  2( 13)

   =       34 + 26

   =     60 meters   of gate metal            metal weighs  2.5 kg per meter

  Total weight equals 60 meters   times    2.5 kg per meter

    Total weight = 60 (2.5)    =     150 kg

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