Consider function h. 31
hir)
1 2x2
4, xco
3r + 10, 0 < I<4
1 > 4
21,
What are the values of the function when I
= 0 and when I = 4?
h(0)
h(4)

56 44 2 4

step-by-step explanation:

4+3x hope you like mark as brainliest✔

answer: 3 x 2 = 6 and 6+0

step-by-step explanation: sum equals addition and twice is multiplication so its

3 x 2 = 6

6+0= 6

identity property of zero

lr = 24

step-by-step explanation:

note that p is the midpoint of lr. to find the measurement of lr, set the equation:

lr = lp + pr

plug in the corresponding numbers to the corresponding variables:

lr = (15) + (9)

simplify:

lr = 24

24 is your measurement of lr.

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