If sinA = cosB, what is the relationship between A and B if A is obuse angled and B is acute angled ?

According to the law of sines, \dfrac{AB}{\sin(\angle C)}=\dfrac{AC}{\sin(\angle B)}

sin(∠C)

AB

=

sin(∠B)

AC

start fraction, A, B, divided by, sine, left parenthesis, angle, C, right parenthesis, end fraction, equals, start fraction, A, C, divided by, sine, left parenthesis, angle, B, right parenthesis, end fraction. Now we can plug the values and solve:

\begin{aligned} \dfrac{AB}{\sin(\angle C)}&=\dfrac{AC}{\sin(\angle B)} \dfrac{5}{\sin(33^\circ)}&=\dfrac{AC}{\sin(67^\circ)} \dfrac{5\sin(67^\circ)}{\sin(33^\circ)}&=AC 8.45&\approx AC \end{aligned}

sin(∠C)

AB

sin(33

∘

)

5

sin(33

∘

)

5sin(67

∘

)

8.45

=

sin(∠B)

AC

=

sin(67

∘

)

AC

=AC

≈AC

,xzgv

step-by-step explanation:

; oqirjg'

i think the answer would be c