What is −3(2a)+−4(−6b)+5(3c) written on standard form. pls help asap​

-6a+24b+15c

Step-by-step explanation:

The given expression is :

−3(2a)+−4(−6b)+5(3c)

We need to write it in the standard form.

We know that,

-3(2) = -6, -4(-6) = 24 and 5(3) = 15

−3(2a)+−4(−6b)+5(3c) = -6a+24b+15c

Hence, the required answer is equal to "-6a+24b+15c".

do you have a picture of the table

ending amount = beginning amount / (2^n)

where "n" = number of half-lives (or elapsed time / half-life)

ending amount = 50 mg / (2 ^10 / 5.3)

ending amount = 50 mg / (2 ^ 1.8867924528)

ending amount = 50 m / 3.6981210597

ending amount = 13.5203794557 mg

or about 13.5 mg remain

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