Pre-image ABCD was dilated to produce image ​A′B′C′D′​ . What is the scale factor from the pre-image to the image? Enter your answer in the box as a fraction in simplest form. $\text{Basic}$ $x$$y$$x^2$$\sqrt{ }$$\frac{x}{ }$ $x\frac{ }{ }$ $x^{ }$$x_{ }$$\degree$$\left(\right)$$\abs{ }$$\pi$$\infty$ Two quadrilaterals labeled A B C D and A-prime, B-prime, C-prime, D-prime. Quadrilateral A B C D is larger than the other quadrilateral, which is to the right of quadrilateral A B C D. Side B C is labeled twelve, and side B-prime, C-prime is labeled nine.

a.

step-by-step explanation:

step 1 distribute 2 to every term in the parentheses

step 2 add 10 on both sides of the equal sign

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

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