If z=sqrt2[cos(-pi/4)+sin(-pi/4]0 a+ bi in rectangular form, then a= _ and b= __ (see photo)
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Mathematics, 23.03.2021 19:50 joannakawata6
If z=sqrt2[cos(-pi/4)+sin(-pi/4]0 a+ bi in rectangular form, then a= _ and b= __ (see photo)
![If z=sqrt2[cos(-pi/4)+sin(-pi/4]0 a+ bi in rectangular form, then a= _ and b= __ (see photo)](/tpl/images/2245/1341/3c93e.jpg)
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