Triangle ABC has vertices A (0, 2), B (5, 4), and C (5, 0). Triangle A′B′C′ has corresponding vertices A′ (–5, –1), B′ (0, 1), and C′ (0, –3). Which of the following describes a translation that would produce triangle A′B′C′ from the pre-image of triangle ABC? Question 18 options: A) To the right five units, up three units. B) To the right five units, down three units. C) To the left five units, up three units. D) To the left five units, down three units.

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)