Identify the graph of 2x^2 + 4xy + 4y^2 = 0 then find theta to the nearest degree.

2x2 + 4xy + 4y2 = 0

2 xx + 4xy +  4yy = 0

...xx + 2xy + y*y  + yy = 0

(x + y)^2  + yy = 0

if  x is a constant

... 2yy + 4xy  - 2xy  + xx = 0

(2yy + 4xy + 2xx -2xx) - 2xy + xx = 0

2(y + x)^2 - 2xx - 2xy + xx = 0

2(y + x)^2 - xx - 2xy  = 0

2(y + x)^2 - xx - 2xy  +yy  - yy = 0  

(x + y)^2  + yy = 0

x = i*y  - y

if  x = r cos a

y = r sin a

cos a )^2  + cos a sina  + sin a)^2  +  sin a)^2 = 0

cos a sin a + sin a)^2 = -1  

Step-by-step explanation:

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step-by-step explanation:

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step-by-step explanation:

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