The daily advertising revenue (in dollars) for a local newspaper is given by the function R(t) = -18t2 + 720t – 103, where t is number of years that the paper has been in production. What is the daily advertising revenue after the paper has been in business for 15 years?

6647

Step-by-step explanation:

The computation of the advertising revenue for 15 years is shown below:

Given that

r(t) = -18t^2 + 720t - 103

where

t = number of years = 15

now put the value of t in the above equation

= -18(15)^2 + 720(15) - 103

= -4050 + 10,800 - 103

= 6647

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)