How do you solve 10≤2x≤x+9? The answer says it's 5≤x≤9 but i have no idea how it got there

Step-by-step explanation:

so why this kind of problem is so confusing is b/c it's 2 problems in one

if you were to expand this it look like this

10 ≤2x

and

2x ≤x+9

This is really saying.. that x has a range.. and that the 1st equations is the lower stop point,  and that the 2nd equations is the upper stop point

once it's taken apart.. I bet you can solve it pretty quickly.

5≤x

and

x ≤9

then just put it back together in that confusing .. yet handy way to write it,

5≤x≤9

school a:

minimum value is 2

maximum value is 22

the lower quartile is 2.5

the median is 10

the upper quartile is 15.5

school b:

minimum value is 9

maximum value is 20

the lower quartile is 12

the median is 16

the upper quartile is 18

box plot for school a isn't symmetrical. the data tails on the right

box plot for school b isn't symmetrical. the data tails on the left

hope i

-lavira: )