Using a quadratic equation A ball is thrown from an initial height of 1 meter with an initial upward velocity of 20 m/s. The ball's height h (in meters) after 1 seconds is given by the
following
h=1+20t-5t2
Find all values of 1 for which the ball's height is 11 meters.
Round your answer(s) to the nearest hundredth.
(If there is more than one answer or )

The ball height is 11 meters at t = 0.59 seconds and t = 3.41 seconds.

Step-by-step explanation:

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

.

This polynomial has roots such that , given by the following formulas:

The height of the ball after t seconds is given by:

Find all values of t for which the ball's height is 11 meters.

This is t for which . So

Simplifying by 5

Which means that

The ball height is 11 meters at t = 0.59 seconds and t = 3.41 seconds.

- 70

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step-by-step explanation: