HELP ME ASAP.
This question is from Algebra Nation.

Step-by-step explanation:

vertex form   y = (x-h)^2 + k      and vertex is at  ( h, k)

the problem has   y = x^2 + 5

then  y = (x - 0)^2 + 5    the vertex is at  ( 0 , 5)  

shift that to the right 3 , then

y = ( x - 3)^2 + 5     now the vertex is at (3,5)    nice

now shift to the left 10  ( to the left is sooner, to the right is later , that why we subtract to go right and add to go left)

y = ( x + 10 )^2 + 5    now the vertex is at ( -10, 5 )    or shifted 10 left

:)

i think the answer is b.

step-by-step explanation:

not 100% sure though.

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40