Help pls

I believe they are not.

Step-by-step explanation:

The reason for this is that in the first algebraic expression there are parentheses which means you must do anything inside the parentheses first. On the other hand, the second expression doesn't have parentheses so you'll end up subtracting 3 from x, also not 100% sure!!

no answer but I talk too u on here tho

Step-by-step explanation:

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step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.