A directed line segment begins at F(10, -2), ends at H(4,6 ), and is divided in the ratio 4 to 2 by G. What are the coordinates of G? Round to the nearest hundredth if necessary.

Question 5 options:

(3.33, 6)

(7.33, 0.67)

(0.67, 7.33)

(6, 3.33)

Step-by-step explanation:

G is 4/6 of the distance from F to H.

Difference of x-coordinates = 4-10 = -6

10 + 4/6 of -6 = 6

Difference of y-coordinates = 6-(-2) = 8

-2 + 4/6 of 8 = 10/3

G(6, 3.33)

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: