What is the solution to the system of equations below?

{3x+4y=(-2)
{2x-4y=(-8)

x = -2 , y = 1

Step-by-step explanation:

add the terms :

3x+2x+4y-4y = -2-8

5x = -10

x = -2

now that x = -2 , plug its value into any of the two equations (we'll take the first)

3*-2 +4y = -2

4y = 4

y = 1

x = -2

y = 1

Step-by-step explanation:

{3x+4y=(-2)

{2x-4y=(-8)

{4y = -2 - 3x

{2x - 4y = -8

Substitute the value of 4y in 2x - 4y = -8

2x - (-2 - 3x) = -8

x= - 2

Substitute the value of x into 2x - 4y = -8

= 2x (-2) - 4y = -8

y = 1