A couple decides to keep having children until they have a girl, at which point they will stop having children. They also agree to having a maximum of three children. The table below shows the probability distribution of X=, equals the number of children such a couple would have. X=# of children 1 2 3
P(X), .5 .25 .25
Given that \mu_X=1.75μ
X
​
=1.75mu, start subscript, X, end subscript, equals, 1, point, 75 children, find the standard deviation of the children such a couple would have.
Round your answer to two decimal places.
\sigma_X\approxσ
X
​
≈sigma, start subscript, X, end subscript, approximately equals
children

ill work on it ig

Step-by-step explanation:

.83

Step-by-step explanation:

Khan academy

0.83 children

Step-by-step explanation:

Khan academy

table 1

step-by-step explanation:

1-16

2-32

4-64

8-128

all multiples of 16

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.