If the area of a rectangle is 64cm squared, how many different perimeters are possible when the dimensions are whole numbers

2 different perimeters, 32 cm and 40 cm

Step-by-step explanation:

Given the area of a rectangle is 64 cm squared.

We know, Area of the rectangle is = length x breath

∴  64 = 8 x 8

Hence the sides can be 8 cm by 8 cm.

So the perimeter of the rectangle is = 8 cm + 8 cm + 8 cm +8 cm

                                                            = 32 cm

Also, Area of the rectangle is = length x breath

∴  64 = 16 x 4

So the perimeter of the rectangle is = 16 cm + 4 cm + 16 cm +4 cm

                                                            = 40 cm  

the correct answer to your question is a. 4^4

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step-by-step explanation: