Two Parallel lines are cut by a transcersal and form a pair of alternate exterior angles. One angle measures (6x + 5) and the other measures (7x+4). Explain how to determine what those angles actually measure?

11° is the measure of the exterior angles

Step-by-step explanation:

Theorem:   Alternate exterior angles are congruent when two parallel lines cut by a transversal.

First we solve for x using the theorem

6x + 5 = 7x + 4

x = 1

Substitute x = 1 into 6x + 5

6(1) + 5 = 6 + 5 = 11°

f

step-by-step explanation:

f

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°