PLEASE HELP!! find the value of c

Step-by-step explanation:

step 1. so you want to convert a quadratic (ax^2 + bx + c) into a perfect square

step 2. therefore c is half of b then squared

step 3. (26/2)^2 = 169

step 4. (-22/2)^2 = 121

step 5. (-13/2)^2 = (-6.5)^2 = 169/4 = 42.25.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer: the answer is ann