Consider triangles CBD and BDE and answer the questions that follows 2.1 Which side is common in both triangles?
2.2 What can be concluded about the heights of A CBD
and A BDE? Give a reason for your answer.
2.31 Using your answers from 2.1 und 2.2 above complete
the following statements:
2.3.1 Area of A CBD
2.3.2 Area of ABDE
2.4 What can be concluded about the area of A CBD and
ABDE?​

Step-by-step explanation:

∠ABD ≅ ∠BDE (given) (1)

m∠ABD + m∠CBD = 180°... (straight line ∠'s)... (2)

From equations (1) & (2)

m∠BDE + m∠CBD = 180°(3)

m∠BDE + m∠CDB = 180°... (straight line ∠'s)... (4)

From equations (3) & (4)

m∠BDE + m∠CBD = m∠BDE + m∠CDB

m∠CBD ≅ m∠CDB.. (Proved)

step-by-step explanation:

given perimeter: 28cm

length: 9cm

atp,

2(l+w)=p of the reactangle

2(9+x)=28

18+2x=28

2x=28-18

x=10/2

x=5

therefore width is 5 cm

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°