Xy=80 solve log x- log y=1

Question: Solve for x and y in the equation.

xy=80 and log x - 2 log y =1

x = 40, y = 2

Step-by-step explanation:

xy = 80.......................... Equation 1

logx-2logy = 1

logx-logy² = 1

Applying the laws of logarithm,

log(x/y²) = log10

x/y² = 10

x  = 10y²......................... Equation 2

Substitute the value of x in therms of y equation 2 into equation 1

10y²(y) = 80

10y³ = 80

y³ = 8

y =

y = 2.

Substitute the value of y into equation 1

2x = 80

x = 80/2

x = 40

Therefore,

x = 40, y = 2

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier