Find the domain and the range of the relation. t = {(10,6), (28,- 10), (42,6), (10,10),(52,10)}
The domain of t = { ? }

domain:{10,28,42,52}

range:{-10,6,10}

Step-by-step explanation:

Hello There!

If you didn´t know the domain is the set of x values

the x values in the given relation are

10,28,42,10 and 52

so the domain is {10,28,42,52}

The range is the set of y values

the y values in the given relations are

6,-10,6,10,10

so the range is {-10,6,10}

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.