Jabal and Michael are walking to school and agree to leave their homes at the same time. Jabal leaves his house walking 2.5 meters per second. Michael leaves his house walking 5 meters per second.
Jabal's house is 15 meters closer to school than Michael's house, therefore he is starting 15 meters closer than Michael.
After how long are the boys walking together? Use any strategy you'd like to solve.

6 seconds

Step-by-step explanation:

Time            Jabal (2.5mps)            Michael (5mps)

Start              15                                   0

1 sec              17.50                              5

2                    20                                  10

3                    22.5                               15

4                    25                                  20

5                    27.5                               25

6                    30                                  30

7

8

9

10

6 sec

Step-by-step explanation:

Let d = distance for Jabal

d + 15 = distance for Michael

t = d/r

d/2.5 = time for Jabal

(d + 15)/5 = time for Michael

The times are equal since they both started walking at the same time.

(d + 15/5 = d/2.5

2.5(d + 15) = 5d

2.5d + 37.5 = 5d

37.5 = 2.5d

d = 15 m. = Jabal's distance

15/2.5 = 6 sec.

this was already solved by me with a different person. if you look it up in the search bar at the top of the page, you will get the answer.

step-by-step explanation:

chase is right because he already been to the swings and he know how far it will be to get there

step-by-step explanation: