Questions 10 through 13 This is the third time that I am asking the same question!

Step-by-step explanation:

10)

P10 = (2,7)

and parallel to y -4x = 5

y = 4x + 5

so any thing with a slope of 4 but going thur P1

y-7 = 4(x-2)

y-7 = 4x -8

10)  y = 4x -1

11)

P11 = (5,-1)

and parallel to

y = -1/2x + 2

anything with a slope of -1/2 but going thur P2

y- (-1) = -1/2(x-5)

y + 1 = -1/2x +5

11)  y = -1/2x + 4

12)

P12 = ( 3, 0 )

-2y + 3x = 0

perpendicular to,  so the slope is reciprocal and opposite sign

3x = 2y

3/2x = y

y = 3/2x

-2/3 is the perpendicular slope

y-0 = -2/3(x-3)

12)  y = -2/3x + 2

13)

P13= ( 6, 3)

3x- y = 6

perpendicular to,  so the slope is reciprocal and opposite sign

3x-6 = y

y = 3x -6

-1/3

y-3 = -1/3(x-6)

y-3 = -1/3x + 2

13)  y = -1/3x + 5

maybe showing the graph would

step-by-step explanation:

-387129 iq