Solving by substitution​

y = -9x -26

=> 9x + y = -26 × 2

=> 18x + 2y = -52 ....(i)

- 2x -7y = -1

=> 2x + 7y = 1 × 9

=> 18x + 63y = 9 ....(ii)

From (i) & (ii) ,

18x + 02y = -52

18x + 63y = 09

-61 y = – 61

=> y = 1

2x + 7y = 1

=> 2x + 7×1 = 1

=> 2x = 1-7

=> x =

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figure c

step-by-step explanation:

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answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°