2.What is the slope-intercept form of a line that contains the points (5, - 5) and has a slope of -3? 3. Write an equation of a line that is parallel to y = - 5/2 x + 3 but travels through the origin? (Note: Parallel lines have the same slope.)

2. y - (-5) = -3 (x - 5)

3. y = -5/2

Step-by-step explanation:

Point intercept form: y - y₁ = m (x - x₁)

Where y and x are just kept as y and x, y₁ and x₁ are the parts of a coordinate, and m = slope.

2. The points are (5, -5) and the slope is -3. Plug this into y - y₁ = m (x - x₁) to get

y - (-5) = -3 (x - 5)

3. As stated, parallel lines have the same slope, so the slope of the line would be -5/2. The origin is (0, 0), so plug these two numbers in.

y - y₁ = m (x - x₁)

y - 0 = -5/2 (x - 0)

y = -5/2

1. 3

2. 4

3. 1

hope this ! have a great day.

-wfz