(2k7 - 476 + 16K5 - 2262 - 6K2)​

=2k^7+16k^5−6k^2−2738

Step-by-step explanation:

Let's simplify step-by-step.

2k^7−476+16k^5−2262−6k^2

=2k^7+−476+16k^5+−2262+−6k^2

Combine Like Terms:

=2k^7+−476+16k^5+−2262+−6k^2

=(2k^7)+(16k^5)+(−6k^2)+(−476+−2262)

=2k^7+16k^5+−6k^2+−2738

=2k^7+16k^5−6k^2−2738

Hope this helps :)

Pl Brainliest

what are the options? ?

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.