Model With Mathematics A photographer is placing photos in a mat for a gallery show.
Each mat she uses is x in, wide on each side.
The total area of each photo and mat is
shown

a. The possible dimensions of the total area are;

The width of the total area is (2·x + 8) inches

The length of the total area is (2·x + 10) inches

b. The dimensions of the photos are as follows;

The length of the photos are 10 inches

The width of the photos are 8 inches

Step-by-step explanation:

a. Given that the area, A = 4·x² + 36·x + 80

We get;

A = 4 × (x² + 9·x + 20) = 4 × (x + 4) × (x + 5) = (2·x + 8)·(2·x + 10)

Therefore, the possible dimensions of the total area (photo + mat) are;

The width of the total area (photo + mat) = (2·x + 8) in.

The length of the total area (photo + mat) = (2·x + 10) in.

b. The dimensions of the photos alone are shorter than the dimensions of the photo and mat combined by 2·x each

Therefore, we have the dimensions of the photos are as follows;

The length of the photo = (2·x + 10) in. - 2·x in. = 10 in.

The width of the photos = (2·x + 8) in. - 2·x in. = 8 in.

d i think

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!