A neighborhood group has $28,000 to spend on improvements to a park. They spend $7,600 on playground equipment and $115 on each tree. Which inequality represents the maximum number of trees, t, that the group can buy? A. 115t + 7,600 ≤ 28,000

B. 115t – 7,600 ≥ 28,000

C. 115t + 7,600 ≥ 28,000

D. 115t – 7,600 ≤ 28,000

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Option (A) is the answer.

A. 115t + 7,600 ≤ 28,000

Step-by-step explanation:

First, you see that the answer to the question has to show that 115t plus or minus 7,600 has to be less than 28,000 because that is how much the neighborhood group has of money to spend. So, that narrows the answers to a or c. The correct answer would be answer A because you need to add 115t and 7,600 because both of those two numbers are the costs for the improvements of the park. Therefore, the correct answer would be A. 115t + 7,600 ≤ 28,000.

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answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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