Tan a + sec a - 1
tan a - sec a + 1
1 + sin a
COS a​

the functions have the same rate of change i think. i narrowed it down to this answer and "the rate of change of tour 1 is greater" but i got it wrong using that answer so im assuming its the answer above. (this is a question i also answered from the iready site if anyone needs a reference)

use distributive property on all like terms and change your signs if you have a double negative or if you have positive/negative

you need to rotate this triangle about the origin 270 degrees clockwise to create the full square.