PLEASE HELP!! The AHS Football team did a weigh in at the start of training camp. The weights of the players were distributed normally with a mean of 98kg and a standard deviation of 6kg. Which of the following curves represents the data? A, B, Or C??

Choice C

Explanation:

The mean is 98, so that's the center of the distribution. This is where the highest point occurs because the most people are clustered around here. This rules out choice A and the answer is between B or C.

One standard deviation above the mean is 98+6 = 104. All we do is add on the standard deviation (6) to the mean (98) to get 104.

One standard deviation below the mean is 98-6 = 92

The graph that has tickmarks at 92 and 104 indicate we are exactly 1 standard deviation from the mean (98)

Similarly, 2 standard deviations above the mean is at 98+2*6 = 98+12 = 110. Or you could say 104+6 = 110.

2 standard deviations below the mean would get us to 98-2*6 = 98-12 = 86

The same idea applies to 3 standard deviations as well.

All of this matches with graph C. We can eliminate graph B by noticing that something like 95 is not a result of 98-6.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.