HELP PLEASE!! Part A: Identify the Minimum, First Quartile, Median, Third Quartile, and Maximum for the data.

64, 53, 60

60, 56, 58

51, 55, 60

A. Minimum: 51, First Quartile: 55, Median: 58, Third Quartile: 60; Maximum: 64

B. Minimum: 51, First Quartile: 55.5, Median: 59, Third Quartile: 60; Maximum: 64

C. Minimum: 51, First Quartile 54.5, Median: 57, Third Quartile: 60; Maximum: 64

D. Minimum: 51, First Quartile: 54, Median: 58, Third Quartile: 60; Maximum: 64

Yes! This is my area!

Step-by-step explanation:

Minimum= 51

Maximum=64

To find the median put the numbers in order

51,53,55,58,60,60,64

no cross off one by one to get the middle number

you end up with 58

first quartile is the upper half so that would be 53

third quartile is the lower half so that wou;d be 60

Hope this helps!

D

Step-by-step explanation:

when you put them in numerical order, you have 51, 53, 55, 56, 58, 60, 60, 60, 64

the minimum is the smallest number in the data set. the maximum is the largest number in the data set.

the median is the measure of center, which indicates the middle number in the data set

the first quartile is the center of the bottom set of the data

the third quartile is the center of the upper set of the data

(the upper and lower sets are indicated by which side of the median they are on)

hope this helped :)

36

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column