Circle A has center of (6, 7), and a radius of 4 and circle B has a center of (2, 4), and a radius of 16.

See solutions below

Explanation

We are to find the equation of circle A and B

The equation of a circle is expressed as;

(x-a)^2 + (y-b)^2 = r^2

(a, b) is the centre and r is the radius

For Circle A that has center of (6, 7), and a radius of 4

Substitute;

(x-6)^2 + (y-7)^2 = 4^2

(x-6)^2+(y-7)^2 = 16

Hence the equation of circle A is (x-6)^2+(y-7)^2 = 16

For circle B:

If circle B has a center of (2, 4), and a radius of 16

The equation is expressed as;

(x-2)^2+(x-4)^2 = 16^2

(x-2)^2+(x-4)^2 = 256

Hence the required equation is (x-2)^2+(x-4)^2 = 256

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}