The Bobcats football coach logged the following yardage gains and losses over four plays of a game. 1. Gain 25x yards.
2. Gain 0.97 yards.
3. Lose 12y yards.
4. Lose 5.2yards.
What is the net yardage for these four plays?
Enter your answer as an expression, like this: 42x+53y

Here's link to the

cutt.ly/tz3yDpb

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.