So in the equation
I understand I have to take the 16 over the equal sign and add 9 to both sides but where does the 6x go I the equation ​

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2

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8

Step-by-step explanation:

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−

±

2

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4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

2

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6

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1

6

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0

x^{2}+6x-16=0

x2+6x−16=0

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1

a={\color{#c92786}{1}}

a=1

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6

b={\color{#e8710a}{6}}

b=6

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−

1

6

c={\color{#129eaf}{-16}}

c=−16

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6

±

6

2

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4

⋅

1

(

−

1

6

)

√

2

⋅

1

Evaluate the exponent

Multiply the numbers

Add the numbers

Evaluate the square root

Multiply the numbers

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6

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1

0

2

To solve for the unknown variable, separate into two equations: one with a plus and the other with a minus.

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6

+

1

0

2

=

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6

−

1

0

2

=

2

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8

your cute btw

b. hannah is playing with her cousin at

mujhko hui na