Álgebra/help There are 3 consecutive integers that add up to 15. What is the least of these integers?

The answers are 4,5,6,

the answer you are looking for is 4

Step-by-step explanation:

the first thing you have to do is define a variable for stuff that you don't know. In this problem, you don't know any of the integers, so you should assign a variable to them.

will put  the first integer as n. The second integer, since it is right after the first, will be n+1. The third integer, since it is right after the second, will be (n+1)+1=n+2. consider the integers 1, 2, and 3. 2 is one more than 1, or in other words, 2=1+1. same for 3, except 3 is two more than 1, so 3=1+2. Since the integers are consecutive, each is one more than the last.We're told that the sum of our three integers is 15. Therefore, n+(n+1)+(n+2)=15 Solving this equation is pretty straightforward:

3n+3=15

3n=12

n=4 That means our first integer is 4. Our second integer is 4+1, or 5, and our third integer is 5+1, or 6. Our answer is confirmed because 4+5+6=15

i hope I helped!!