Mathematics, 18.03.2021 02:20 raymondleggett44
In circle O, chords AC BD intersect at E. If m\overgroup{AB} AB =95° and m\overgroup{CD} CD =45°. AE is x+2, CE is x, BE is 5, and ED is 3 in length. m∠AEB = m∠CED = m\overgroup{AD}=m AD = m\overgroup{BC}\ =\m BC = m\angle AED\ =\m∠AED = m\angle BEC\ =\m∠BEC = AE = CE =
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In circle O, chords AC BD intersect at E. If m\overgroup{AB} AB =95° and m\overgroup{CD} CD =45°. AE...
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