If f (1)=10 and f (n)=f (n-1)-3 then find the value of f (4)

Given that the  height of the plant f(n), in cm, after n days:

To find n when f(n) = 11.04 cm

i.e. in 2.5 days

2) n cannot go up to infinity

If maximum growth is h, then domain is (0, )

3) Put n=0

y intercept = 10 cm.

4) This gives the initial height of the plant i.e. when n =0

5) Average rate of change = 10(1.04)^n ln 1.04

6) n =1,2,3,4,5

n 1      2               3        4                         5

f(n) 10.4 10.816 11.24864 11.6985856 12.16652902

(this is got by substituting n =1,2,3,4,5.

7) Avg rate of change in interval (a,b) = change in f(n)/change in n

22 dimes and 9 nickels

step-by-step explanation:

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)