Sam kicks a ball off of a rooftop. After t seconds, its height, h (in feet), is given by the formula h (t) = -16t^2 + 64t + 80.

a. What is the maximum height reached by the ball?

b. When did the ball reach its maximum height?

c. When will the ball hit the ground? (Do algebraically)

d. What is the height of the ball after 1 second?

a. 144m

b. After 2 secs

c. Ball hits the ground after 5 secs.

d. 128m

Step-by-step explanation:

A

To find max height, find derivative of equation, let it equal zero, and sub in value into original equation:

h(t) = -16t² + 64t + 80

h'(t)=-32t+64

-32t+64=0

32t=64

t=2

h(2) = -16(2²) + 64(2) + 80

h(2) = -64+128+80 = 144m

B

When h=144, t=2. Therefore, the ball reaches its max height after 2 secs.

C

When the ball hits the ground, h=0:

-16t² + 64t + 80=0

t²-4t-5=0 (simplified)

(t-5)(t+1)=0

t=5 and t=-1

Discount t=-1 (time cant be neg).

Ball hits the ground after 5 secs.

D

Find h when t=1:

h(t) = -16t² + 64t + 80

h(1) = -16(1²) + 64(1) + 80

h(1) = -16+64+80

h(1) = 128m

circle area = pi * radius^2

if diameter = 10 then radius = 5

circle area = pi * 5^2

circle area = pi * 25

circle area = 78.5398163397 square units

step-by-step explanation:

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)