Probabilities. Please help

In throwing a dice, there are 6 possible outcomes, namely 1, 2, 3, 4, 5 and 6.

P=(no. of favourable outcomes)/(no. of possible outcomes)

When we multiply the probability of an event with no. of trials, the we get the expected frequency of that event.

1) P(getting 1)=1/6

expected frequency of getting 1

=P(getting)1)×no. of trials

=1/6×600=100

But it is given that one is scored 200 times, so it makes a large difference from expected frequency, which is 100.

Therefore, the dice is not fair.

2) P(getting a tail)=0.3

estimate for the number of times the coin will land on a tail

=expected frequency of getting a tail

=P(getting a tail)×no. of trials

=0.3×150=45

3)P(getting a six)=2/3

expected frequency of getting a six

=P(getting a six)×no. of trials

=2/3×300=200

4)P(getting a three)=0.5

expected frequency of getting a three

=P(getting a three)×350

=0.5×350=175

the answer is 0.5 mpm

step-by-step explanation:

the line goes half way through the square each time (which is 0.5 or half of course) so that would mean its 0.5 mpm.