The correlation coefficient for the scatterplot above is r = 0.41. The point (18, 78) appears to be an outlier since it doesn’t follow the general pattern of the data, so we want to determine how much it influences the value of r. To do this, we remove the outlier from the data set and recalculate r. How will removing the outlier affect the value of the correlation coefficient, r?

well the answer to that is xoxoxo

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

the answer on ed. is:

c. "the graph of f(x) has exactly two x-intercepts."

hope i could someone! : )