I NEED HELP AGAIN PLZ

cut the polygon into fourths.

since it's a square, the line values of each of the fourth's lines will equate.

find the area of one of the little triangles first.

area of triangle = 1/2 * a * b

area of triangle = 1/2 * 7 * 7 = 24.5

there're 4 triangles.

24.5*4 = 98

98 yds ^ 2

The area of your square is 98 yd²

Step-by-step explanation:

The given information about the polygon is half of the diagonal length. Since 7 yds are only half of the diagonal length, we know to add another 7yds to complete the line. Therefore we have 14 as our diagonal length.

Additional info:

side lengtha = 9.8994949366117 yd

diagonalq = 14 yd

perimeterP = 39.597979746447 yd

areaA = 98 yd²

Formulas used:

Area of a square:

A = a2

Perimeter of a Square

P = 4a

Polygon diagonals of a square

q = √(2a2) = a√2

Side of a Square

a = √A

a = P/4

a = q / √2

step-by-step explanation:

let pq = qr = rs = x, and xz = y and zu = z.

if the horizontal lines are parallel, then corresponding segments are in proportion:

substitute:

therefore 3 = y = z.

xu = y + z → xu = 3 + 3 = 6

answer: you will have more water.