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Mathematics, 18.03.2021 01:30 Idontwantto1057

Pls help will give brainliest


Pls help will give brainliest

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Mathematics, 22.06.2019 01:00, SpeechlessZzz9920
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
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Mathematics, 22.06.2019 02:30, wibi1963
Me answer this question: -2/3p + 1/5 - 1 + 5/6p i think the simplified expression is 1/6p - 4/5 correct me if i'm wrong, and explain it! if i have it right, just tell me. you so
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