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So the surface area consists of 2 triangles and 3 different rectangles

Triangle area = 1/2 * 8cm * 6cm = 24cm²

Rectangle a area (bottom one) = 17cm * 8cm = 136cm²

Rectangle b area (the one to the left) = 17cm * 6cm = 102cm²

To calculate Rectangle c we need to know the hypotenuse of our triangles

Formula for the hypotenuse is c =

so c = = 10

Rectangle c area = 17cm * 10cm = 170cm²

So the surface area is 2 * 24cm² + 136cm² + 102cm² + 170cm² = 456cm²

The volume is 1/2 * h * a * b = 1/2 * 6cm * 8cm * 17cm = 408cm³

hi there!

the answer will be d: 2

x² + 11x + 18 < 0  

[-11 ± sqrt(121 - 72)]/2 = (-11 ± 7)/2  

solution: (-9, -2)

step-by-step explanation: