Now you will attempt to copy your original triangle using one of its angles: • Draw a line segment, DE, of any length anywhere on the coordinate plane, but not on top of AABC.
• Choose one of the angles on AABC. From point D, create an angle of the same size as the angle you chose. Then draw a ray from D through
the angle. You should now have an angle that is congruent to the angle you chose on MBC.
• Create a point anywhere outside the mouth, or opening of the angle you created. The point will initially be named F by the tool, but you
should rename it point G. Now draw a ra from Ethrough G such that it intersects the first ray. Your creation should be a closed shape
resembling a triangle.
• Label the point of intersection of the two rays F, and draw ADEF by creating a polygon through points D, E, and F.
. Click on point, and move it around. By moving point G, you can change ZDEFand ZEFD, while keeping ZFDEfixed.
Take a screenshot of your results for one position of G, save it, and insert the image in the space below.
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the equation for this situation is y=122+45. to solve the equation you would add 45 and 122 to get a total of 167lbs. in conclusion, grace's weight eight weeks ago was 167lbs.  

step-by-step explanation:

the multiplicative inverse of a fraction a/b is b/a. for the multiplicative inverse of a real number, divide 1 by the number. for example, the reciprocal of 5 is one fifth 1/5 or 0.2, and the reciprocal of 0.25 is 1 divided by 0.25, or 4.

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: