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P(4≤x≤7) = 2/3

Step-by-step explanation:

We'll begin by obtaining the sample space (S) i.e possible outcome of rolling both dice at the same time. This is illustrated below:

1,1 1,2 1,3 1,4 1,5 1,6

2,1 2,2 2,3 2,4 2,5 2,6

3,1 3,2 3,3 3,4 3,5 3,6

4,1 4,2 4,3 4,4 4,5 4,6

5,1 5,2 5,3 5,4 5,5 5,6

6,1 6,2 6,3 6,4 6,5 6,6

Adding the outcome together, the sample space (S) becomes:

2 3 4 5 6 7

3 4 5 6 7 8

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

7 8 9 10 11 12

Next, we shall obtain the event of 4≤x≤7. This is illustrated below:

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

4 5 6 7

Finally, we shall determine P(4≤x≤7). This can be obtained as follow:

Element in the sample space, n(S) = 36

Element in 4≤x≤7, n(4≤x≤7) = 24

Probability of 4≤x≤7, P(4≤x≤7) = ?

P(4≤x≤7) = n(4≤x≤7) / nS

P(4≤x≤7) = 24/36

P(4≤x≤7) = 2/3

the answer is c

hope this !

2x^2+5x+17

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