PLEASE HELP ASAP A ball is thrown straight up from the top of a building 144 ft tall with an initial velocity of 48 ft per second. The height
s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t^2.
Find the maximum height attained by the ball.

The maximum height attained by the ball is of 180 feet.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

Where

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is .

In this question:

We have that:

Which is a quadratic equation with .

The maximum height is the value of s, which is the output, at the vertex. So

The maximum height attained by the ball is of 180 feet.

1/2*qr*rs

step-by-step explanation: