Question 28 28. The time taken for 5,000 to amount to * 5,408 at 4% per annum compoun
interest is
years.
a) 1
b) 2
c) 3
d) 4
ОА
OB
Ос
Oo​

Given Rate of interest is r=8%=0.08

Principal Amount is A=5,000

Time is t years

Interest is compounded yearly twice ⟹n=2

Amount =P(1+

n

r

)

nt

=5000×(1+

2

0.08

)

2t

=5,408

(1.0816)

t

=

5000

5408

⟹t=1

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3